Question 1 · Hard
A 10 mL mixture of CH₄ and C₂H₆ burns completely in excess oxygen and gives 14 mL of CO₂. All volumes are at the same temperature and pressure. Find the volume of O₂ consumed.
- A35 mL
- B26 mL
- C20 mL
- D28 mL
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Answer: B · 26 mL
Let CH₄ = x and C₂H₆ = y: x + y = 10 and x + 2y = 14, so y = 4 mL and x = 6 mL. Oxygen used = 6 × 2 + 4 × 3.5 = 26 mL. Check by atoms: 14 CO₂ need 28 O, and 48 H give 24 H₂O needing 24 O, a total of 52 O = 26 O₂.
- A: This treats the whole mixture as C₂H₆.
- C: This treats the whole mixture as CH₄.
- D: This counts the oxygen in CO₂ only and forgets the oxygen in the water formed.
Remember this
At the same temperature and pressure, gas volumes combine in the mole ratio of the equation (Gay-Lussac's law).