Question 1 · Hard
A patient's cells give 3+ with one monoclonal IgM anti-D and 0 with a second licensed anti-D made from a different clone. Controls are valid. What is the most likely explanation?
- ATwo red cell populations after transfusion
- BA positive DAT giving a false-positive result
- CA partial D lacking the second clone's epitope
- DA weak D type 1 with too few D sites
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Answer: C · A partial D lacking the second clone's epitope
Each monoclonal anti-D recognizes one D epitope. A partial D protein lacks some epitopes, so it can react strongly with one clone and not at all with another clone that targets a missing epitope. Weak D, a positive DAT or a mixed population would affect both reagents in a similar way. The patient is managed as D-negative for transfusion and RhIG, and RHD genotyping can identify the variant.
- A: A mixed population would give mixed-field reactions with both reagents.
- B: IgM reagents at immediate spin are rarely affected by a positive DAT, and the controls are valid.
- D: Weak D gives weak reactions with both reagents, not 3+ and 0.