Question 1 · Medium
A 14-year-old girl with acute asthma in the paediatric casualty is given nebulised salbutamol, and her wheeze settles within minutes. Through which pathway does salbutamol relax her bronchial smooth muscle?
- ABeta-2 receptor, cAMP rise and reduced MLCK activity
- BBeta-2 receptor, cGMP rise and calcium entry
- CDirect opening of potassium channels by the drug
- DMuscarinic block with less IP3 formation
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Answer: A · Beta-2 receptor, cAMP rise and reduced MLCK activity
Salbutamol stimulates beta-2 receptors, which act through Gs to raise cAMP. Protein kinase A then reduces cytosolic calcium and phosphorylates myosin light chain kinase, lowering its activity, so the myosin light chains are less phosphorylated and the muscle relaxes. Smooth muscle contraction depends on calcium-calmodulin activating MLCK, rather than on troponin. Ipratropium, a muscarinic blocker, relaxes bronchi by a different route and is added in severe attacks.
- B: Beta-2 receptors act through cAMP, not cGMP, and relaxation needs less calcium, not more.
- C: Salbutamol acts through its receptor and second messenger, not by opening channels directly.
- D: Muscarinic blockade is the mechanism of ipratropium, not salbutamol.