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MedExams

Gravitation

10 NEET-UG practice questions on Gravitation, part of Physics. The first 10 are below; the first 5 with answers and explanations (tap Show answer after you have chosen), the rest in Learn with a free account.

  1. Question 1 · Medium

    Assertion A: Ignoring air resistance and the Earth's rotation, the escape speed from the Earth's surface is the same for every launch direction. Reason R: The orbital speed of a satellite in a given orbit does not depend on the mass of the satellite. Choose the correct answer.

    1. ABoth A and R are correct but R is not the correct explanation of A
    2. BA is not correct but R is correct
    3. CBoth A and R are correct and R is the correct explanation of A
    4. DA is correct but R is not correct
    Show answer

    Answer: A · Both A and R are correct but R is not the correct explanation of A

    Escape needs (1/2)mv² = GMm/R; energy is a scalar, so the direction of launch does not enter. Orbital speed √(GM/r) has no satellite mass in it, so R is also true. But R concerns orbital motion and does not explain why direction is irrelevant to escape.

    • B: A is correct, since the energy condition has no direction in it.
    • C: R is true but is about mass in an orbit, not about launch direction.
    • D: R is a correct statement, since m cancels in the force balance.

    Remember this

    Escape speed √(2gR) depends only on the planet; neither the projectile's mass nor its direction appears.

  2. Question 2 · Medium

    An object weighs 72 N on the Earth's surface. What is its weight at a height R/2 above the surface, where R is the radius of the Earth?

    1. A48 N
    2. B36 N
    3. C18 N
    4. D32 N
    Show answer

    Answer: D · 32 N

    Distance from the centre = 3R/2, so g' = g/(3/2)² = 4g/9. Weight = 72 × 4/9 = 32 N.

    • A: This uses an inverse first power of the distance.
    • B: This uses the depth formula, 1 − h/R.
    • C: This takes the distance from the centre as 2R.

    Remember this

    Use g' = g/(1 + h/R)² when h is comparable to R; the approximation 1 − 2h/R then fails.

  3. Question 3 · Hard

    A 400 kg satellite circles the Earth at an orbital radius of 2R. How much energy must be supplied to shift it to a circular orbit of radius 4R? Take R = 6400 km and g = 10 m/s² at the surface.

    1. A1.6 × 10⁹ J
    2. B3.2 × 10⁹ J
    3. C5.12 × 10¹⁰ J
    4. D6.4 × 10⁹ J
    Show answer

    Answer: B · 3.2 × 10⁹ J

    Total energy in an orbit of radius r is E = −GMm/(2r) = −mgR²/(2r). So E₁ = −mgR/4 and E₂ = −mgR/8, and the energy needed is mgR/8. Numerically, 400 × 10 × 6.4 × 10⁶/8 = 3.2 × 10⁹ J.

    • A: This uses −GMm/(4r) for the total energy, half the correct value.
    • C: This uses mgh with h = 2R, taking g as constant.
    • D: This counts only the change in potential energy, ignoring the fall in kinetic energy.

    Remember this

    Moving a satellite outward takes ΔE = (GMm/2)(1/r₁ − 1/r₂), half the rise in potential energy.

  4. Question 4 · Medium

    Given below are two statements: Statement I: The orbital speed of a satellite close to the Earth's surface is 1/√2 times the escape speed from the surface. Statement II: A heavier projectile needs a larger escape speed from the Earth than a lighter one. Choose the correct answer.

    1. AStatement I is incorrect but Statement II is correct
    2. BBoth Statement I and Statement II are incorrect
    3. CStatement I is correct but Statement II is incorrect
    4. DBoth Statement I and Statement II are correct
    Show answer

    Answer: C · Statement I is correct but Statement II is incorrect

    Near the surface, v₀ = √(gR) and vₑ = √(2gR), so v₀ = vₑ/√2 and Statement I holds. The mass of the projectile cancels in the energy condition, so the escape speed is the same for all masses and Statement II fails.

    • A: This reverses the two truth values.
    • B: Statement I is right, since vₑ = √2 v₀.
    • D: Statement II is wrong, as mass cancels in the energy condition.

    Remember this

    A heavier body needs more escape energy, but exactly the same escape speed.

  5. Question 5 · Easy

    Treating the Earth as a sphere of uniform density, what is the acceleration due to gravity at its centre, if its value at the surface is g?

    1. AZero
    2. Bg/4
    3. C2g
    4. Dg/2
    Show answer

    Answer: A · Zero

    Inside a uniform Earth, g at depth d is g(1 − d/R). At the centre, d = R, so the value is zero.

    • B: This is the value at a height R above the surface, not at the centre.
    • C: This wrongly assumes g grows on going deeper.
    • D: This is the value at depth R/2, not at the centre.

    Remember this

    Below the surface g falls linearly to zero at the centre; above it g falls as 1/r².

  6. Question 6 · Easy

    Kepler's law of areas, for a planet going round the Sun, follows from the conservation of which quantity?

    1. AKinetic energy
    2. BPotential energy
    3. CLinear momentum
    4. DAngular momentum

    Answer and explanation in LearnFree account

  7. Question 7 · Easy

    A planet's elliptical orbit around the Sun is drawn with four marked positions. At which position is its orbital speed greatest?

    Figure: MedExams
    Ellipse with the Sun at one focus and four labelled positions on the orbit.
    1. APosition T
    2. BPosition R
    3. CPosition Q
    4. DPosition P

    Answer and explanation in LearnFree account

  8. Question 8 · Medium

    Earth is treated as a sphere of radius R and uniform density. Variation of the acceleration due to gravity g with distance r from its centre, gₛ being the surface value, is correctly shown by which graph?

    Figure: MedExams
    Four graphs labelled A to D of g against distance from the centre, each with the surface R marked.
    1. AGraph B
    2. BGraph C
    3. CGraph A
    4. DGraph D

    Answer and explanation in LearnFree account

  9. Question 9 · Hard

    A satellite of mass m is shifted from Orbit 1 to Orbit 2 around a planet of radius R, where surface gravity is g. The drawing marks heights above the surface. What minimum energy is needed for the shift?

    Figure: MedExams
    Planet with two concentric orbits, labelled by heights measured from the surface.
    1. AmgR
    2. BmgR/12
    3. CmgR/4
    4. DmgR/6

    Answer and explanation in LearnFree account

  10. Question 10 · Medium

    Two satellites move in the circular orbits drawn around one planet, A having a period of 3 h. What are the period of B and the ratio of orbital speed of A to that of B?

    Figure: MedExams
    Planet with two circular orbits of radii marked r and 4r, carrying satellites A and B.
    1. A24 h and 1/2
    2. B48 h and 4
    3. C24 h and 2
    4. D12 h and 2

    Answer and explanation in LearnFree account

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