Question 1 · Hard
Suppose force F, acceleration A and time T are chosen as the base quantities of a system of units. In this system, what are the dimensions of angular momentum?
- A[F A² T³]
- B[F A T³]
- C[F A⁻¹ T³]
- D[F A T²]
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Answer: B · [F A T³]
Mass = F/A and length = AT² (from acceleration × time²). Angular momentum = mass × length²/time = (F/A)(A²T⁴)/T = FAT³. Check: angular momentum = length × linear momentum = (AT²)(FT) = FAT³.
- A: This takes mass as F instead of F/A.
- C: This writes length with a wrong power of A.
- D: This gives the dimensions of energy, F × length.
Remember this
First write mass and length in the new base quantities, then substitute into the usual formula.