Question 1 · Hard
To prepare 100 mL of acetate buffer at pH 5.06, a technician mixes 0.1 M acetic acid (pKa 4.76) with 0.1 M sodium acetate. Which volumes are correct?
- A50.0 mL sodium acetate + 50.0 mL acetic acid
- B66.7 mL sodium acetate + 33.3 mL acetic acid
- C57.4 mL sodium acetate + 42.6 mL acetic acid
- D33.3 mL sodium acetate + 66.7 mL acetic acid
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Answer: B · 66.7 mL sodium acetate + 33.3 mL acetic acid
By Henderson-Hasselbalch, 5.06 = 4.76 + log ([acetate]/[acetic acid]), so log ratio = 0.30 and the ratio is 2:1. Both solutions are 0.1 M, so the volumes are in the same ratio: two-thirds sodium acetate and one-third acetic acid. That is 66.7 mL and 33.3 mL. A pH above the pKa always needs more salt than acid.
- A: Equal volumes give a pH equal to the pKa, 4.76.
- C: 57.4 : 42.6 uses e^0.30 (natural log) instead of 10^0.30.
- D: Inverting the ratio gives a pH of 4.46, below the pKa.