Question 1 · Hard
Glucose by GOD-POD is read against distilled water: reagent blank 0.05, standard (100 mg/dL) 0.45 and test 0.65. What is the glucose concentration?
- A144 mg/dL
- B67 mg/dL
- C133 mg/dL
- D150 mg/dL
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Answer: D · 150 mg/dL
Subtract the reagent blank from both readings: test 0.65 - 0.05 = 0.60 and standard 0.45 - 0.05 = 0.40. Glucose = (0.60 / 0.40) x 100 = 150 mg/dL. Leaving the blank in gives 144 mg/dL, and inverting the ratio gives 67 mg/dL. Setting the instrument to zero with the reagent blank instead of water removes this step.
- A: 144 mg/dL comes from not subtracting the blank (0.65/0.45 x 100).
- B: 67 mg/dL comes from inverting the ratio (0.40/0.60 x 100).
- C: 133 mg/dL comes from correcting only the test reading (0.60/0.45 x 100).