Question 1 · Hard
A 45-year-old man collects a 24-hour urine of 2,160 mL with urine creatinine 90 mg/dL. Serum creatinine is 1.5 mg/dL. His creatinine clearance, not corrected for body surface area, is:
- A90 mL/min
- B60 mL/min
- C2,160 mL/min
- D135 mL/min
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Answer: A · 90 mL/min
First convert the volume to a flow rate: 2,160 mL ÷ 1,440 min = 1.5 mL/min. Clearance = U × V ÷ P = 90 × 1.5 ÷ 1.5 = 90 mL/min. Leaving out V gives 60, leaving out P gives 135, and dividing the volume by 60 instead of 1,440 gives 2,160. The commonest error in practice is an incomplete collection, which is checked from the total creatinine excreted per day.
- B: 60 mL/min is U ÷ P alone, leaving out the urine flow.
- C: 2,160 mL/min comes from dividing the volume by 60 minutes instead of 1,440.
- D: 135 mL/min is U × V without dividing by the serum creatinine.