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MedExams

Biomolecules

21 NEET-UG practice questions on Biomolecules, part of Zoology. The first 21 are below; the first 5 with answers and explanations (tap Show answer after you have chosen), the rest in Learn with a free account.

  1. Question 1 · Medium

    Malonate inhibits succinic dehydrogenase because it

    1. Aresembles fumarate and oxidises the enzyme's haem group
    2. Bdenatures the enzyme by breaking its tertiary structure
    3. Cresembles succinate in structure and competes for the active site
    4. Dbinds far from the active site and changes the enzyme's shape
    Show answer

    Answer: C · resembles succinate in structure and competes for the active site

    Malonate closely resembles the substrate succinate, so it competes for the active site and blocks binding. This is competitive inhibition.

    • A: Malonate resembles the substrate, not the product.
    • B: Malonate does not denature the protein.
    • D: Malonate acts at the substrate-binding site.

    Remember this

    A competitive inhibitor resembles the substrate; such inhibitors are used in controlling bacterial pathogens.

  2. Question 2 · Medium

    Without any enzyme, about 200 molecules of H₂CO₃ form in an hour. With carbonic anhydrase, about 600,000 molecules form every second. By roughly how many times does the enzyme speed up the reaction?

    1. AAbout 2 × 10⁹ times
    2. BAbout 1.8 × 10⁵ times
    3. CAbout 3000 times
    4. DAbout 10⁷ times
    Show answer

    Answer: D · About 10⁷ times

    Per hour, the enzyme gives 600,000 × 3600 ≈ 2.16 × 10⁹ molecules, and 2.16 × 10⁹ ÷ 200 ≈ 1.08 × 10⁷. Per second, the uncatalysed rate is 200 ÷ 3600 = 1/18, and 600,000 × 18 gives the same value.

    • A: This forgets to divide by the uncatalysed 200.
    • B: This converts seconds only to minutes.
    • C: This ignores the difference between hour and second.

    Remember this

    Carbonic anhydrase speeds this reaction about 10 million times.

  3. Question 3 · Medium

    Given below are two statements: Statement I: Arachidonic acid has 16 carbon atoms, including the carboxyl carbon. Statement II: Lecithin is a phospholipid. Choose the correct answer.

    1. AStatement I is incorrect but Statement II is correct
    2. BBoth Statement I and Statement II are incorrect
    3. CStatement I is correct but Statement II is incorrect
    4. DBoth Statement I and Statement II are correct
    Show answer

    Answer: A · Statement I is incorrect but Statement II is correct

    Palmitic acid has 16 carbons; arachidonic acid has 20, including the carboxyl carbon, so Statement I is wrong. Lecithin is a phospholipid found in cell membranes.

    • B: Statement II is true of lecithin.
    • C: Statement I is the false one, not Statement II.
    • D: Statement I gives the carbon count of palmitic acid.

    Remember this

    Palmitic acid has 16 carbons; arachidonic acid has 20; both counts include the carboxyl carbon.

  4. Question 4 · Hard

    Consider these statements on enzyme cofactors: A. The protein part of a holoenzyme is the apoenzyme. B. A coenzyme associates with the apoenzyme only during catalysis. C. The coenzymes NAD and NADP contain the vitamin niacin. D. Zinc is a cofactor of carboxypeptidase. Choose the correct answer.

    1. AB, C and D only
    2. BA and C only
    3. CA, B, C and D
    4. DA, C and D only
    Show answer

    Answer: C · A, B, C and D

    All four match NCERT. Also, removing a cofactor destroys catalytic activity, which shows that it is essential.

    • A: A is also true, since the protein part is the apoenzyme.
    • B: B and D are also true.
    • D: B is also true, since a coenzyme's binding is transient.

    Remember this

    Holoenzyme equals apoenzyme plus cofactor; cofactors are prosthetic groups, coenzymes or metal ions.

  5. Question 5 · Medium

    Match List-I with List-II. List-I (secondary metabolite) A. Concanavalin A B. Abrin C. Vinblastin D. Morphine List-II (group) I. Drug II. Lectin III. Alkaloid IV. Toxin

    1. AA-I, B-IV, C-II, D-III
    2. BA-II, B-IV, C-I, D-III
    3. CA-IV, B-II, C-I, D-III
    4. DA-II, B-IV, C-III, D-I
    Show answer

    Answer: B · A-II, B-IV, C-I, D-III

    Concanavalin A is a lectin and abrin a toxin, while vinblastin is a drug and morphine an alkaloid.

    • A: This swaps lectin and drug.
    • C: This swaps lectin and toxin.
    • D: This swaps drug and alkaloid.

    Remember this

    Abrin and ricin are toxins; morphine and codeine are alkaloids; vinblastin and curcumin are drugs.

  6. Question 6 · Hard

    Match List-I with List-II. List-I (enzyme class) A. Oxidoreductases B. Transferases C. Lyases D. Ligases List-II (reaction catalysed) I. Removal of groups by means other than hydrolysis, leaving double bonds II. Linking two compounds, as in forming C-O or C-N bonds III. Transfer of a group other than hydrogen between a pair of substrates IV. Oxidation of one substrate with reduction of another

    1. AA-IV, B-I, C-III, D-II
    2. BA-III, B-IV, C-I, D-II
    3. CA-IV, B-III, C-II, D-I
    4. DA-IV, B-III, C-I, D-II

    Answer and explanation in LearnFree account

  7. Question 7 · Easy

    Compared with the Earth's crust, which element is far more abundant, by weight, in the human body?

    1. ASilicon
    2. BCarbon
    3. CMagnesium
    4. DSodium

    Answer and explanation in LearnFree account

  8. Question 8 · Medium

    An experimenter keeps one sample of a human enzyme at 4 °C and another at 90 °C for an hour, then tests both at 37 °C. Which result is expected?

    1. ANeither sample shows any activity at 37 °C
    2. BBoth samples show full activity at 37 °C
    3. CThe cold sample shows activity, but the heated sample does not
    4. DThe heated sample shows activity, but the cold sample does not

    Answer and explanation in LearnFree account

  9. Question 9 · Hard

    Given below are two statements: Statement I: As a polypeptide is conventionally written, the left-end amino acid is N-terminal and the right-end amino acid is C-terminal. Statement II: Adult human haemoglobin has two alpha and two beta subunits, which is a quaternary structure. Choose the correct answer.

    1. ABoth Statement I and Statement II are correct
    2. BStatement I is incorrect but Statement II is correct
    3. CBoth Statement I and Statement II are incorrect
    4. DStatement I is correct but Statement II is incorrect

    Answer and explanation in LearnFree account

  10. Question 10 · Medium

    Which statements on polysaccharides are correct? A. Cellulose is a homopolymer of glucose. B. Inulin is a polymer of fructose. C. The arthropod exoskeleton has chitin, a complex polysaccharide. D. Glycogen is a heteropolymer of glucose and fructose.

    1. AA, B and C only
    2. BB, C and D only
    3. CA and B only
    4. DA, C and D only

    Answer and explanation in LearnFree account

  11. Question 11 · Medium

    In peroxidase and catalase, which break down hydrogen peroxide, haem acts as a

    1. Acoenzyme
    2. Bapoenzyme
    3. Cprosthetic group
    4. Dmetal ion cofactor

    Answer and explanation in LearnFree account

  12. Question 12 · Medium

    Consider these statements on amino acids: A. Tyrosine, phenylalanine and tryptophan are aromatic. B. Lysine is an acidic amino acid. C. Glutamic acid is an acidic amino acid. D. Valine is a basic amino acid. Choose the correct answer.

    1. AA and D only
    2. BB and D only
    3. CA and C only
    4. DA, B and C only

    Answer and explanation in LearnFree account

  13. Question 13 · Easy

    When iodine solution is added to a starch sample, a blue colour appears. This is because

    1. AI₂ binds at the reducing end of the chain
    2. BI₂ oxidises each glucose unit in the chain
    3. CI₂ is held in the helical parts of starch
    4. DI₂ breaks starch down into glucose

    Answer and explanation in LearnFree account

  14. Question 14 · Hard

    Arrange the steps of an enzyme's catalytic action in the correct order. A. An enzyme-product complex is formed B. The substrate binds to the active site C. The enzyme alters its shape and fits more tightly around the substrate D. The active site breaks the chemical bonds of the substrate

    1. AC, B, D, A
    2. BB, C, D, A
    3. CB, C, A, D
    4. DB, D, C, A

    Answer and explanation in LearnFree account

  15. Question 16 · Medium

    Match List-I with List-II. List-I (protein) A. Collagen B. GLUT-4 C. Insulin D. Antibody List-II (function) I. Hormone II. Fights infectious agents III. Intercellular ground substance IV. Enables glucose transport into cells

    1. AA-III, B-I, C-IV, D-II
    2. BA-IV, B-III, C-I, D-II
    3. CA-III, B-IV, C-I, D-II
    4. DA-III, B-IV, C-II, D-I

    Answer and explanation in LearnFree account

  16. Question 17 · Medium

    Lipids have molecular weights that do not exceed about 800 Da, yet they appear in the acid-insoluble fraction of a tissue extract. This is because

    1. Aacid treatment raises the molecular weight of lipids
    2. Blipids polymerise into chains in the acid
    3. Clipids bond covalently to proteins during grinding
    4. Dmembranes broken on grinding form water-insoluble vesicles

    Answer and explanation in LearnFree account

  17. Question 18 · Easy

    A ribozyme is

    1. Aa polysaccharide that stores ribose
    2. Ba lipid that speeds up a reaction
    3. Ca nucleic acid that behaves like an enzyme
    4. Da protein that binds to the ribosome

    Answer and explanation in LearnFree account

  18. Question 19 · Medium

    Two separate, unbranched polypeptide chains have 40 and 25 amino acids. How many peptide bonds do they have in total?

    1. A63
    2. B62
    3. C64
    4. D65

    Answer and explanation in LearnFree account

  19. Question 20 · Medium

    Assertion A: An enzyme speeds up a reaction by lowering its activation energy. Reason R: An enzyme is used up in the reaction it catalyses. Choose the correct answer.

    1. AA is correct but R is not correct
    2. BBoth A and R are correct but R is not the correct explanation of A
    3. CBoth A and R are correct and R is the correct explanation of A
    4. DA is not correct but R is correct

    Answer and explanation in LearnFree account

  20. Question 21 · Easy

    Adenosine consists of

    1. Aadenine joined to a pentose sugar
    2. Badenine, a pentose sugar and a phosphate
    3. Cadenine alone, without any sugar
    4. Dadenine joined to a phosphate

    Answer and explanation in LearnFree account

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