Question 1 · Hard
Results: anti-A 0, anti-B 0; A1 cells 4+, B cells 4+. Group O screening cells and the autocontrol are both 2+ at room temperature. The best next step is:
- ARepeat the reverse grouping with cold-autoadsorbed plasma
- BType the cells with anti-H lectin for Bombay
- CReport group O and issue group O plasma
- DRepeat the forward grouping with anti-A1 lectin
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Answer: A · Repeat the reverse grouping with cold-autoadsorbed plasma
The positive autocontrol points to a cold autoantibody, often anti-I, reacting with every cell at room temperature. Removing it by autoadsorption in the cold lets the reverse grouping be read clearly. A Bombay phenotype would give a negative autocontrol, because the patient's own cells lack H. The patient appears to be group O, but this is confirmed after the interference is removed.
- B: A Bombay patient's anti-H does not react with their own H-negative cells, so the autocontrol would be negative.
- C: The ABO discrepancy should be resolved before reporting.
- D: The forward grouping is not in doubt here.