Question 1 · Hard
A 52-year-old man with a body surface area of 2.10 m² is investigated for proteinuria. He collects an overnight 12-hour urine from 20:00 to 08:00, emptying his bladder at 20:00 and discarding that urine, and including the 08:00 void. Urine volume 600 mL; urine creatinine 120 mg/dL [10.6 mmol/L]. Serum creatinine drawn at 08:00 is 0.9 mg/dL [80 µmol/L]. The collection is judged complete. What is his creatinine clearance corrected to a body surface area of 1.73 m²?
- A46 mL/min/1.73 m²
- B92 mL/min/1.73 m²
- C135 mL/min/1.73 m²
- D111 mL/min/1.73 m²
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Answer: B · 92 mL/min/1.73 m²
Clearance = (urine creatinine x urine volume) / (serum creatinine x time) = (120 x 600) / (0.9 x 720) = 72,000 / 648 = 111 mL/min. The collection lasted 12 hours, so the time is 720 minutes, not the 1,440 minutes of a 24-hour collection. Correcting to standard body size: 111 x 1.73 / 2.10 = 92 mL/min/1.73 m². A larger person makes and filters more creatinine, so the corrected value is lower than the raw one. Urine and serum creatinine must be in the same units for the calculation.
- A: 46 uses 1,440 minutes, but this was a 12-hour (720-minute) collection.
- C: 135 comes from multiplying by 2.10/1.73, which inverts the body size correction.
- D: 111 mL/min is the uncorrected clearance; it was not adjusted for his larger body size.