Question 1 · Hard
A 40-year-old man from Uganda is treated in Abu Dhabi with intravenous artesunate for Plasmodium falciparum malaria. His day-0 thick film density was 20,000 asexual parasites/µL. On day 3 he is still febrile. The day-3 thick film shows 180 asexual parasites and 60 gametocytes counted against 200 white cells, and his WBC count that morning is 3.5 × 10^9/L. The hospital protocol flags possible early treatment failure when the day-3 asexual density is 25% or more of the day-0 density. Which result is correct?
- A4,200/µL, below 25% of day 0
- B31,500/µL, above 25% of day 0
- C3,150/µL, below 25% of day 0
- D7,200/µL, above 25% of day 0
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Answer: C · 3,150/µL, below 25% of day 0
Thick-film density = (asexual parasites counted ÷ white cells counted) × WBC count per µL. With the measured WBC count of 3,500/µL: 180 ÷ 200 × 3,500 = 3,150 asexual parasites/µL. This is about 16% of the day-0 density of 20,000/µL, below the 25% flag, so the parasites are clearing despite the fever. Gametocytes are counted and reported separately, because artesunate does not clear mature gametocytes quickly and their presence is not a sign of treatment failure. The assumed value of 8,000 white cells/µL is used only when no WBC count is available.
- A: 4,200 wrongly includes the gametocytes in the asexual density.
- B: 31,500 comes from dividing by 20 instead of by 200 white cells.
- D: 7,200 assumes 8,000 white cells/µL, but the measured count must be used.