Question 1 · Hard
A 48-year-old woman has a lipid profile at a non-fasting workplace screening, drawn 2 hours after a large lunch: total cholesterol 5.6 mmol/L (217 mg/dL), HDL cholesterol 1.3 mmol/L (50 mg/dL), triglyceride 3.3 mmol/L (292 mg/dL), calculated LDL cholesterol 2.8 mmol/L (108 mg/dL). One week later, after a 12-hour fast, her results are total cholesterol 5.6 mmol/L, HDL cholesterol 1.3 mmol/L and triglyceride 1.3 mmol/L (115 mg/dL). The laboratory calculates LDL cholesterol with the Friedewald equation in mmol/L: LDL = total cholesterol - HDL - (triglyceride ÷ 2.2). What is her fasting LDL cholesterol, and why does it differ from the first result?
- A4.0 mmol/L; meal triglyceride inflated the VLDL term
- B3.7 mmol/L; meal triglyceride inflated the VLDL term
- C3.7 mmol/L; HDL cholesterol falls after a fatty meal
- D4.3 mmol/L; Friedewald cannot be used after a meal
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Answer: B · 3.7 mmol/L; meal triglyceride inflated the VLDL term
Fasting LDL = 5.6 - 1.3 - (1.3 ÷ 2.2) = 5.6 - 1.3 - 0.59 = 3.7 mmol/L (143 mg/dL). Total and HDL cholesterol were the same on both days, so the whole difference comes from the triglyceride term. After a meal, chylomicrons and their remnants raise triglyceride but carry little cholesterol, so triglyceride ÷ 2.2 overestimates VLDL cholesterol and the non-fasting Friedewald LDL comes out too low (2.8 mmol/L). Dividing triglyceride by 5, the mg/dL factor, gives 4.0 mmol/L, and leaving the triglyceride term out gives the non-HDL cholesterol of 4.3 mmol/L. Non-fasting profiles are acceptable for screening, but when triglyceride is raised, a fasting repeat, a direct LDL or non-HDL cholesterol gives a truer picture.
- A: 4.0 mmol/L comes from dividing triglyceride by 5, the factor for mg/dL.
- C: Her HDL cholesterol is 1.3 mmol/L on both days, so it did not change.
- D: 4.3 mmol/L is total minus HDL cholesterol, which is non-HDL cholesterol, not LDL.