Question 1 · Hard
A 34-year-old man is brought in drowsy about 8 hours after drinking an unknown liquid in a garage. An arterial blood gas shows pH 7.09, bicarbonate 7 mmol/L and lactate 13.6 mmol/L on the blood gas analyzer. Plasma drawn at the same time gives lactate 2.3 mmol/L on the chemistry analyzer (reference 0.5-2.2), anion gap 31 mmol/L (reference 8-16), osmolal gap 24 mOsm/kg (reference < 10), no ethanol and a normal beta-hydroxybutyrate. Both samples were analyzed within 15 minutes. The manufacturer lists the gas analyzer's lactate oxidase sensor as cross-reacting with glycolate; the chemistry method does not. The most likely cause is:
- AMethanol ingestion
- BMetformin lactic acidosis
- CIsopropanol ingestion
- DEthylene glycol ingestion
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Answer: D · Ethylene glycol ingestion
Two lactate results that differ by more than 11 mmol/L on samples taken together point to an interfering substance rather than true lactic acidosis. Ethylene glycol is metabolized to glycolate, which accumulates and is oxidized by some lactate oxidase sensors, so the blood gas analyzer reads it as lactate. Glycolate and oxalate also explain the high anion gap acidosis, and the raised osmolal gap shows that unmetabolized glycol is still present. Methanol forms formate, which does not create a lactate gap, and in metformin toxicity both methods would show a high lactate. Isopropanol raises the osmolal gap without acidosis. A lactate gap should prompt an urgent ethylene glycol level and early fomepizole.
- A: Methanol produces formate, which does not interfere with lactate methods, so there would be no lactate gap.
- B: True lactic acidosis would give a high lactate by both methods.
- C: Isopropanol raises the osmolal gap and acetone but does not cause a high anion gap acidosis.