Question 1 · Hard
A Staphylococcus aureus from a 45-year-old man's skin abscess gives these results: oxacillin MIC 4 µg/mL (S ≤2, R ≥4); cefoxitin disk 26 mm (R ≤21, S ≥22); PBP2a latex test on growth taken next to a cefoxitin disk, negative; mecA and mecC PCR, not detected; nitrocefin test on induced growth, strongly positive; penicillin resistant. With clavulanate added, the oxacillin MIC falls to 0.5 µg/mL. Which mechanism best explains the raised oxacillin MIC?
- AmecC-encoded PBP2a homologue
- BHyperproduction of penicillinase
- CModified native PBPs (MODSA)
- DmecA-encoded PBP2a
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Answer: B · Hyperproduction of penicillinase
The isolate lacks mecA, mecC and PBP2a, and its cefoxitin zone is susceptible, so it is not MRSA. The strong beta-lactamase reaction and the fall in oxacillin MIC when clavulanate is added show that the enzyme itself is slowly breaking down oxacillin. This borderline phenotype (BORSA) is caused by hyperproduction of staphylococcal penicillinase and gives oxacillin MICs of about 1-8 µg/mL. Modified native PBPs (MODSA) can also raise the oxacillin MIC slightly, but a beta-lactamase inhibitor does not reverse that effect. Cefoxitin is a poor substrate for the penicillinase, which is why its zone stays susceptible.
- A: mecC was not detected, and mecC strains usually test cefoxitin resistant.
- C: Altered native PBPs are not reversed by clavulanate.
- D: mecA and PBP2a were both negative.